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Moving Charges and Magnetism

Magnetic force on moving charges and currents, the Biot-Savart law, Ampere's law, and the cyclotron — how electric currents create and respond to magnetic fields.

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Reading time~9 min
Revision time~3 min
Last updated2026-07-19
1 Read the chapter ~9 min

🎯 Key Points

  • Force on a moving charge: F = qv×B = qvB sinθ — zero when v is parallel/antiparallel to B, maximum when perpendicular; force does NO work since it's always perpendicular to v
  • Force on a current-carrying conductor: F = IL×B = BIL sinθ
  • Biot-Savart law gives B due to a current element; key results: straight wire B=μ₀I/2πr, circular coil centre B=μ₀NI/2R, solenoid B=μ₀nI
  • Two parallel wires carrying current in the SAME direction attract; OPPOSITE directions repel — this defines the SI unit ampere
  • Cyclotron frequency f=qB/2πm — independent of speed/radius, depends only on charge, mass, and field strength
Magnetic Field Lines Around a Straight WireIfield forms concentric circles around the wire (right-hand rule)

The magnetic field around a long straight current-carrying wire forms concentric circles, with direction given by the right-hand rule (point thumb along I, fingers curl in the direction of B).

Magnetic Force on a Moving Charge

  • The Lorentz force on a charge q moving with velocity v in field B is F = qv × B, with magnitude F = qvB sinθ, where θ is the angle between v and B
  • The force is always perpendicular to both v and B, so it changes the direction of motion but never the speed — magnetic force does no work on a moving charge
  • If v is perpendicular to a uniform B, the charge moves in a circle of radius r = mv/qB; if v has a component along B too, the path becomes a helix
  • If v is parallel or antiparallel to B (θ=0° or 180°), the force is zero and the charge travels in a straight line, completely unaffected by the field

Magnetic Force on a Current-Carrying Conductor

  • A straight conductor of length L carrying current I in field B experiences force F = IL × B = BIL sinθ
  • This is the working principle behind the electric motor: a current loop placed in a magnetic field experiences a torque that makes it rotate (see below)

Sources of Magnetic Field: The Biot-Savart Law

  • Biot-Savart law: dB = (μ₀/4π) × I·dl × r̂/r² — gives the magnetic field contribution from a small current element
  • Long straight wire: B = μ₀I/2πr
  • Circular coil at centre: B = μ₀NI/2R (N = number of turns, R = radius)
  • Solenoid (ideal, long): B = μ₀nI inside, where n = turns per unit length; field outside is nearly zero

Ampere's Circuital Law

  • ∮B·dl = μ₀I_enclosed — the line integral of B around any closed loop equals μ₀ times the current enclosed by that loop
  • This is the magnetic analogue of Gauss's law in electrostatics, and gives a much faster route to B for highly symmetric situations (straight wire, solenoid, toroid) than directly applying the Biot-Savart law

Force Between Two Parallel Currents — Defining the Ampere

  • Two long parallel wires carrying currents I₁ and I₂, separated by distance d, exert a force per unit length on each other: F/L = μ₀I₁I₂/2πd
  • Currents in the SAME direction attract; currents in OPPOSITE directions repel
  • This force defines the SI unit of current: one ampere is the current that, when flowing through two infinitely long parallel wires 1 m apart, produces a force of exactly 2×10⁻⁷ N per metre of length between them

Torque on a Current Loop and the Moving Coil Galvanometer

  • A current loop of area A carrying current I in a uniform field B experiences torque τ = NIAB sinθ, where θ is the angle between the loop's normal and B — this torque tends to align the loop's magnetic moment with B
  • A moving coil galvanometer suspends a coil in a radial magnetic field (created by curved pole pieces), so the torque is proportional to current at every deflection angle, giving a linear, easy-to-read scale
  • Galvanometer sensitivity increases with larger N, A, or B, or a smaller spring/torsion constant — though this trades off against the instrument's response time

The Cyclotron

  • A cyclotron accelerates charged particles using a perpendicular magnetic field (which bends the path into a circle) combined with an alternating electric field (which accelerates the particle each time it crosses the gap between two D-shaped electrodes)
  • Cyclotron frequency f = qB/2πm is independent of the particle's speed or orbit radius — this is exactly what allows a fixed-frequency alternating voltage to keep accelerating the particle even as its radius keeps growing

Motion of a Charge in a Magnetic Field

  • Circular motion (v ⊥ B): the magnetic force supplies the centripetal force, qvB = mv²/r, giving radius r = mv/qB = p/qB (p = momentum)
  • Time period: T = 2πm/qB and frequency f = qB/2πm — both independent of speed and radius; a faster particle simply traces a larger circle in the same time
  • Helical motion: if v makes an angle θ with B, split v into v‖ = v cosθ (unaffected, constant along B) and v⊥ = v sinθ (circular); the path is a helix of radius r = mv sinθ/qB
  • Pitch (distance advanced per revolution) = v‖ × T = (2πm/qB)·v cosθ

Magnetic Field on the Axis of a Circular Loop

  • On the axis of a circular loop of radius R, N turns, carrying current I, at distance x from the centre: B = μ₀NIR² / [2(R² + x²)^(3/2)]
  • At the centre (x = 0): B = μ₀NI/2R (the standard result)
  • Far on the axis (x ≫ R): B ≈ μ₀NIR²/2x³ = μ₀·(2m)/(4π x³), where m = NIA is the magnetic dipole moment — identical in form to the axial field of an electric dipole
  • The field direction along the axis is given by the right-hand rule (curl fingers along I, thumb points along B)

Solenoid and Toroid (Ampere's Law)

  • Long solenoid: applying Ampere's law to a rectangular loop gives a uniform interior field B = μ₀nI (n = turns per unit length), directed along the axis; the field outside is essentially zero
  • At the open end of a solenoid, the field falls to about half the interior value: B_end ≈ ½μ₀nI
  • Toroid (a solenoid bent into a ring): B = μ₀NI/2πr inside the core, where N is the total number of turns and r the mean radius; the field is confined entirely within the core and is zero both inside the central hole and outside the toroid
Magnetic field lines of a solenoid shown in cross-section, with dots marking current out of the page along the top row of turns and crosses marking current into the page along the bottom row, giving a strong uniform field along the axis inside and a weak spread-out field outside

Solenoid field: nearly uniform and axial inside (B = μ₀nI), weak outside — the cross-section shows current out of the page (dots) and into the page (crosses). Image: Geek3, CC BY-SA 3.0, via Wikimedia Commons.

Magnetic Dipole Moment of a Current Loop

  • A planar current loop of N turns, area A, carrying current I, behaves as a magnetic dipole with moment m = NIA, directed along the loop's normal (right-hand rule); unit: A·m²
  • In a uniform field B it feels a torque τ = m × B = NIAB sinθ and has potential energy U = −m·B = −mB cosθ (minimum when aligned)
  • The orbital motion of an electron in an atom constitutes a tiny current loop with magnetic moment; the smallest unit is the Bohr magneton μ_B = eh/4πm ≈ 9.27×10⁻²⁴ A·m²

Converting a Galvanometer: Ammeter and Voltmeter

  • A galvanometer (resistance G, full-scale current I_g) is converted to an ammeter by connecting a small shunt resistance S in parallel: S = I_g·G/(I − I_g), where I is the desired full-scale current; an ideal ammeter has very low resistance and is connected in series
  • It is converted to a voltmeter by connecting a large resistance R in series: R = V/I_g − G, for full-scale voltage V; an ideal voltmeter has very high resistance and is connected in parallel
  • Adding a shunt lowers the effective resistance and increases the current range; adding a series resistor raises resistance and increases the voltage range

🚀 JEE Advanced Edge

Velocity selectors and mass spectrometers: When perpendicular E and B fields act on a charged particle, it travels in a straight line, undeflected, only when qE = qvB, i.e. v = E/B — independent of the charge's sign or magnitude. This is why velocity selectors filter particles of one specific speed regardless of charge, a key step before measuring charge-to-mass ratio in a mass spectrometer.

Why a charge moving along a field line feels nothing: Since magnetic force depends on qv×B, it vanishes both for v=0 (stationary charge) and for v parallel to B — a charged particle can travel right along a field line forever without ever being deflected. This is a frequently tested conceptual trap distinguishing magnetic force from electric force, which acts on any charge whether moving or not.

Worked problem: Two long straight parallel wires 0.05 m apart carry currents of 3 A and 5 A in the same direction. Find the force per unit length between them. Approach: F/L = μ₀I₁I₂/(2πd) = (4π×10⁻⁷ × 3 × 5)/(2π × 0.05) = (4×10⁻⁷×15)/0.1 = 6×10⁻⁵ N/m, and the force is attractive since the currents flow in the same direction.

2 Revise ~3 min before the exam

📐 Formula Sheet

  • Lorentz force: F = q(v × B) = qvB·sinθ  |  combined: F = qE + q(v × B)
  • Force on a wire: F = BIL·sinθ
  • Circular path of a charge: r = mv/qB  |  Period: T = 2πm/qB (independent of speed)
  • Biot–Savart: dB = (μ₀/4π)·I·dl·sinθ/r²
  • Long straight wire: B = μ₀I/2πr
  • Centre of a circular loop: B = μ₀I/2R  |  Solenoid: B = μ₀nI
  • Ampère's law: ∮B·dl = μ₀Ienclosed
  • Two parallel wires: F/L = μ₀I₁I₂/2πd — attract if currents are parallel, repel if antiparallel
3 Practice apply it

✍️ Worked Examples

Example 1 — Radius of a charged particle's path
Q: A proton (m = 1.67 × 10⁻²⁷ kg, q = 1.6 × 10⁻¹⁹ C) enters a 0.5 T field at 10⁶ m/s, perpendicular to it. Find the radius of its path.
Step 1 — Use r = mv/qB.
Step 2 — Substitute: r = (1.67 × 10⁻²⁷ × 10⁶)/(1.6 × 10⁻¹⁹ × 0.5).
Step 3 — Compute: numerator = 1.67 × 10⁻²¹; denominator = 8 × 10⁻²⁰; r ≈ 0.021 m ≈ 2.1 cm.
Answer: ≈ 2.1 cm. Note: the magnetic force does no work — it changes direction only, never speed.

Example 2 — Field from a long wire
Q: Find the magnetic field 5 cm from a long straight wire carrying 10 A.
Step 1 — Use B = μ₀I/2πr, with μ₀ = 4π × 10⁻⁷.
Step 2 — Substitute: B = (4π × 10⁻⁷ × 10)/(2π × 0.05).
Step 3 — Simplify: the π cancels ⇒ B = (2 × 10⁻⁷ × 10)/0.05 = 4 × 10⁻⁵ T.
Answer: 4 × 10⁻⁵ T. Shortcut: B = 2 × 10⁻⁷ × I/r is the same formula with constants folded in.

Example 3 — Force between parallel wires
Q: Two parallel wires 1 m apart each carry 5 A in the same direction. Find the force per metre and its direction.
Step 1 — Use F/L = μ₀I₁I₂/2πd = 2 × 10⁻⁷ × I₁I₂/d.
Step 2 — Substitute: F/L = 2 × 10⁻⁷ × (5 × 5)/1 = 5 × 10⁻⁶ N/m.
Step 3 — Direction: currents are parallel, so the wires attract.
Answer: 5 × 10⁻⁶ N/m, attractive. Note: this force is what historically defined the ampere.

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Frequently Asked Questions — Moving Charges and Magnetism

What are the key concepts in Moving Charges and Magnetism?
Magnetic force on moving charges and currents, the Biot-Savart law, Ampere's law, and the cyclotron — how electric currents create and respond to magnetic fields.
Is Moving Charges and Magnetism important for NEET & JEE?
Yes. Moving Charges and Magnetism is part of the Physics Class 12 NCERT syllabus and is directly tested in NEET and JEE examinations. StudyHub provides structured notes, diagrams, and practice questions covering all exam-level subtopics.
How can I practice Moving Charges and Magnetism questions on StudyHub?
Open StudyHub and select Physics → Moving Charges and Magnetism. Choose Easy, Medium, or Hard difficulty. Hard-tier questions are at NEET & JEE level with full step-by-step explanations.

References

  1. NCERT Class 12 Physics Textbook — Chapter: Moving Charges and Magnetism
  2. CBSE Curriculum — Physics (Class 12)
  3. NTA NEET UG Official Syllabus — subject-wise topic list
  4. NTA JEE Main Official Syllabus — subject-wise topic list