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⚛️ Physics  ·  Class 12  ·  NEET & JEE

Current Electricity

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

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Reading time~6 min
Revision time~2 min
Last updated2026-07-19
1 Read the chapter ~6 min

🎯 Key Points

  • V=IR; R=ρL/A; Series: R_eq=ΣRᵢ (current same, voltage splits); Parallel: 1/R_eq=Σ(1/Rᵢ) (voltage same, current splits)
  • KCL: current in = current out at a junction (charge conservation); KVL: sum of EMFs and IR drops around any loop = 0
  • Terminal voltage V=E−Ir while discharging; short-circuit current I_sc=E/r
  • Wheatstone bridge balanced when P/Q=R/S (galvanometer shows zero current)
  • Potentiometer uses a null (zero-current) method, making it more accurate than a voltmeter for measuring EMF

Ohm's Law and Resistance

SeriesbatteryR1R2I (same in R1, R2)ParallelbatteryR1R2I1I2

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

  • V = IR; R = ρL/A (ρ = resistivity)
  • Temperature dependence: R = R₀(1 + αΔT)
  • Series: R = ΣRᵢ; Parallel: 1/R = Σ(1/Rᵢ)
  • Power: P = VI = I²R = V²/R
Circuit diagram showing resistors R1 and R2 connected in parallel with each other, and that parallel combination connected in series with resistor R3 between two terminals

Series and parallel combination: R₁ and R₂ in parallel (1/R = 1/R₁ + 1/R₂) then in series with R₃. Image: Omegatron, CC BY-SA 3.0, via Wikimedia Commons.

Kirchhoff's Laws

  • KCL: sum of currents at a junction = 0 (charge conservation)
  • KVL: sum of EMFs and potential drops in a loop = 0 (energy conservation)

Cells and Batteries

  • Terminal voltage: V = E - Ir (E = EMF, r = internal resistance)
  • Short circuit current: I_sc = E/r
  • Cells in series: E_total = ΣEᵢ, r_total = Σrᵢ

Measuring Instruments

  • Wheatstone bridge: balanced when P/Q = R/S (no current through galvanometer)
  • Potentiometer: null method; more accurate than voltmeter
  • Meter bridge: variation of Wheatstone bridge
Wheatstone bridge circuit with nodes A, B, C and D, known resistors R1, R2 and R3, unknown resistor Rx, a detector across the bridge arm between C and B, and a cell connected across A and D

Wheatstone bridge: at balance the detector reads zero and R₁/R₂ = Rₓ/R₃, which is how an unknown resistance is measured. Image: jjbeard, Public Domain, via Wikimedia Commons.

Drift Velocity, Mobility and Current Density

  • Drift velocity v_d: the small average velocity (typically ~10⁻⁴ m/s) that free electrons acquire opposite to the applied field, superimposed on their random thermal motion; v_d = eEτ/m, where τ is the mean relaxation time between collisions
  • Current–drift relation: I = neAv_d, where n is the free-electron density, A the cross-sectional area, e the electronic charge
  • Mobility: μ = v_d/E = eτ/m — drift velocity per unit field (units m²/V·s); larger mobility means a better conductor
  • Current density: J = I/A = nev_d; microscopic (vector) form of Ohm's law: J = σE, where σ = 1/ρ is the conductivity
  • Although v_d is tiny, current appears almost instantly everywhere because the electric field propagates through the wire at nearly the speed of light

Resistivity and Its Temperature Dependence

  • Resistivity ρ = m/(ne²τ) depends on the material, not on dimensions; R = ρL/A
  • Metals (conductors): resistivity increases with temperature — ρ = ρ₀[1 + α(T − T₀)], α > 0, because more frequent collisions reduce τ
  • Semiconductors and insulators: resistivity DECREASES with temperature (α negative), as heating frees more charge carriers (n rises sharply, outweighing the fall in τ)
  • Alloys like manganin and constantan have very low, nearly temperature-independent α — used for standard resistance coils
  • Superconductors have exactly zero resistivity below a critical temperature

Meter Bridge and Potentiometer

  • Meter bridge is a practical Wheatstone bridge on a 1 m wire; at balance (null point at length l from one end): unknown R = S · l/(100 − l), where S is the known resistance in the other gap
  • Potentiometer compares potentials by a null method, drawing zero current at balance — so it measures the true EMF of a cell (unlike a voltmeter, which draws current and reads terminal voltage V < E)
  • Potential gradient along the wire: k = V/L; unknown EMF E = k·l, where l is the balancing length
  • Comparing two EMFs: E₁/E₂ = l₁/l₂ (ratio of balancing lengths)
  • Measuring internal resistance: r = R(l₁ − l₂)/l₂, where l₁ balances the open-cell EMF and l₂ balances the terminal voltage with external resistance R connected

Combination of Cells

  • Series (n cells, each EMF E, internal resistance r): E_eq = nE, r_eq = nr; current through external R is I = nE/(R + nr) — advantageous when R ≫ r
  • Parallel (m identical cells): E_eq = E, r_eq = r/m; current I = E/(R + r/m) = mE/(mR + r) — advantageous when R ≪ r
  • Mixed grouping (m rows in parallel, each of n cells in series): maximum current is delivered when external resistance R = nr/m (impedance matching)
  • If cells of unequal EMF are connected in parallel, use the general result: E_eq/r_eq = Σ(Eᵢ/rᵢ) with 1/r_eq = Σ(1/rᵢ)

🚀 JEE Advanced Edge

Wheatstone bridge with unbalanced condition: When the bridge is NOT balanced, you can't use P/Q=R/S directly — instead apply Kirchhoff's laws fully (set up loop equations) to find the galvanometer current, or use the more general "delta-to-star" / Thevenin equivalent technique for complex resistor networks.

Cells in combination with internal resistance: For n identical cells in series (each EMF E, internal resistance r) driving external resistance R: I = nE/(R+nr). For the same n cells in parallel: I = E/(R+r/n). Series is better when R≫r; parallel is better when R≪r (maximises current in each regime).

Worked problem: A battery of EMF 10V and internal resistance 1Ω is connected to an external resistance of 4Ω. Find the terminal voltage and power delivered to the external resistor. Approach: I=E/(R+r)=10/5=2A. Terminal voltage V=E−Ir=10−2(1)=8V. Power=I²R=4×4=16W.

2 Revise ~2 min before the exam

📐 Formula Sheet

  • Current: I = Q/t = nAvde  |  Drift velocity: vd = eEτ/m
  • Ohm's law: V = IR  |  Resistance: R = ρL/A
  • Resistivity vs temperature: ρT = ρ₀(1 + αΔT)
  • Series: Req = R₁ + R₂  |  Parallel: 1/Req = 1/R₁ + 1/R₂
  • Power: P = VI = I²R = V²/R
  • EMF: ε = V + Ir, so I = ε/(R + r)
  • Kirchhoff: junction rule ΣI = 0 (charge conservation); loop rule ΣV = 0 (energy conservation)
  • Wheatstone bridge (balanced): P/Q = R/S, and no current flows through the galvanometer
3 Practice apply it

✍️ Worked Examples

Example 1 — Internal resistance of a cell
Q: A cell of emf 2 V and internal resistance 0.5 Ω drives a 3.5 Ω resistor. Find the current and the terminal voltage.
Step 1 — Total resistance: R + r = 3.5 + 0.5 = 4 Ω.
Step 2 — Current: I = ε/(R + r) = 2/4 = 0.5 A.
Step 3 — Terminal voltage: V = ε − Ir = 2 − (0.5)(0.5) = 1.75 V.
Answer: I = 0.5 A, V = 1.75 V. Note: the terminal voltage is always below the emf while current is drawn; they are equal only on open circuit.

Example 2 — Resistors in a mixed network
Q: Two 6 Ω resistors in parallel are connected in series with a 2 Ω resistor across a 10 V supply. Find the total current.
Step 1 — Parallel pair: 1/R = 1/6 + 1/6 = 2/6 ⇒ R = 3 Ω.
Step 2 — Add the series resistor: Rtotal = 3 + 2 = 5 Ω.
Step 3 — Ohm's law: I = V/R = 10/5 = 2 A.
Answer: 2 A. Shortcut: two equal resistors in parallel always give half of one of them.

Example 3 — Effect of stretching a wire
Q: A wire of resistance 4 Ω is stretched to twice its length. Find its new resistance.
Step 1 — Stretching conserves volume: if L doubles, A must halve.
Step 2 — Use R = ρL/A: L → 2L and A → A/2, so R → ρ(2L)/(A/2) = 4ρL/A.
Step 3 — So R quadruples: R' = 4 × 4 = 16 Ω.
Answer: 16 Ω. General rule: R ∝ L², so stretching to n times the length multiplies R by n².

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Frequently Asked Questions — Current Electricity

What are the key concepts in Current Electricity?
Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.
Is Current Electricity important for NEET & JEE?
Yes. Current Electricity is part of the Physics Class 12 NCERT syllabus and is directly tested in NEET and JEE examinations. StudyHub provides structured notes, diagrams, and practice questions covering all exam-level subtopics.
How can I practice Current Electricity questions on StudyHub?
Open StudyHub and select Physics → Current Electricity. Choose Easy, Medium, or Hard difficulty. Hard-tier questions are at NEET & JEE level with full step-by-step explanations.

References

  1. NCERT Class 12 Physics Textbook — Chapter: Current Electricity
  2. CBSE Curriculum — Physics (Class 12)
  3. NTA NEET UG Official Syllabus — subject-wise topic list
  4. NTA JEE Main Official Syllabus — subject-wise topic list