Below are 51 practice questions on Sexual Reproduction in Flowering Plants, sorted Easy → Hard. Tap “Show answer & explanation” under any question to check yourself. Want the full theory first? Read the Sexual Reproduction in Flowering Plants notes.
Sexual Reproduction in Flowering Plants — Practice Questions with Answers
51 free MCQs on Sexual Reproduction in Flowering Plants with worked answers and explanations. Flower structure, pollination, double fertilization, and seed/fruit development — the highest-scoring Class 12 biology chapter in NEET.
Take the timed Sexual Reproduction in Flowering Plants quiz →Easy — 17 questions
Q1.
The flower is the organ of _____ reproduction in flowering plants:
- A Vegetative
- B Sexual
- C Asexual
- D All types of
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Answer: B. Sexual
Why: The flower is the reproductive organ of angiosperms (flowering plants). It contains stamens (male) and carpels (female).
Q2.
Pollen grains are produced in the:
- A Pistil, the female reproductive structure
- B Ovary, where ovules later develop into seeds
- C Anther of the stamen
- D Petal, the colorful part attracting pollinators
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Answer: C. Anther of the stamen
Why: Pollen grains (male gametophytes) are produced in the anthers of stamens. They contain the male gametes (sperm cells).
Q3.
The transfer of pollen from anther to stigma is called:
- A Fertilization
- B Germination
- C Pollination
- D Dispersal
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Answer: C. Pollination
Why: Pollination is the transfer of pollen from the anther (stamen) to the stigma (carpel) of the same or another flower.
Q4.
The female reproductive part of a flower is the:
- A Stamen, the male reproductive structure
- B Petal, the often brightly colored part
- C Carpel (pistil)
- D Sepal, the protective outer floral whorl
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Answer: C. Carpel (pistil)
Why: The carpel (pistil) is the female part, consisting of stigma, style, and ovary. Eggs (ovules) are inside the ovary.
Q5.
After fertilization, the ovule becomes the:
- A Fruit
- B Seed
- C Flower
- D Pollen
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Answer: B. Seed
Why: After fertilization, the ovule develops into the seed. The ovary wall (and sometimes other parts) develops into the fruit.
Q6.
After fertilization, the ovary develops into the:
- A Seed
- B Fruit
- C Pollen
- D Leaf
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Answer: B. Fruit
Why: The ovary wall develops into the fruit (pericarp) after fertilization. The fruit protects and aids in seed dispersal.
Q7.
Self-pollination occurs when:
- A Pollen is carried across a field by air currents
- B Pollen from the same flower or same plant fertilizes the ovule
- C Bees or other insects carry pollen between separate plants
- D Pollen floats on water to reach a different plant
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Answer: B. Pollen from the same flower or same plant fertilizes the ovule
Why: Self-pollination: pollen from a flower reaches the stigma of the same flower or another flower on the same plant. Results in less genetic diversity.
Q8.
Which agent is most important for pollination in wind-pollinated flowers?
- A Insects
- B Water
- C Wind
- D Animals
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Answer: C. Wind
Why: Anemophily (wind pollination): pollen is light, dry, and produced in large amounts. Flowers are often small, lack petals/scent. E.g., grasses, maize, wheat.
Q9.
Vegetative reproduction in plants includes:
- A Formation of seeds after fertilization
- B Production of spores in sporangia only
- C Bulbs, runners, rhizomes, tubers (asexual)
- D Combination of seed and spore production together
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Answer: C. Bulbs, runners, rhizomes, tubers (asexual)
Why: Vegetative (asexual) reproduction: new plants from vegetative parts: bulbs (onion), runners (strawberry), rhizomes (ginger), tubers (potato), corms, etc.
Q10.
Double fertilization is unique to:
- A Gymnosperms such as pine and cycads
- B Ferns that reproduce via free-living gametophytes
- C Angiosperms (flowering plants)
- D Mosses with a dominant gametophyte generation
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Answer: C. Angiosperms (flowering plants)
Why: Double fertilization: unique to angiosperms. One sperm fertilizes the egg (→ zygote); another fuses with two polar nuclei (→ triploid endosperm).
Q11.
The endosperm in a seed provides:
- A A hard protective coat around the seed
- B Nourishment for the developing embryo
- C Auxins and gibberellins that trigger germination
- D Storage of water absorbed during imbibition
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Answer: B. Nourishment for the developing embryo
Why: Endosperm is nutritive tissue in angiosperm seeds. It stores starch, oils, and proteins to nourish the developing embryo during germination.
Q12.
Germination is the process by which:
- A Seeds are scattered away from the parent plant
- B A seed begins to grow into a new plant
- C Pollen grains mature inside the anther
- D Flower buds differentiate on the shoot apex
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Answer: B. A seed begins to grow into a new plant
Why: Germination: activation of a dormant seed. The embryo begins growing, the radicle emerges first, then the shoot. Requires water, oxygen, and suitable temperature.
Q13.
Cross-pollination promotes:
- A Genetic uniformity across successive generations
- B Genetic variation and vigor (hybrid vigor)
- C Reproduction of the pollinating insect species itself
- D Dormancy mechanisms that delay seed germination
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Answer: B. Genetic variation and vigor (hybrid vigor)
Why: Cross-pollination between different plants promotes genetic variation and often results in hybrid vigor (heterosis) -- more robust offspring.
Q14.
Seed dispersal by wind (anemochory) is aided by:
- A Hooks and spines that cling to animal fur
- B Wings, tufts of hair (pappus), or lightweight seeds
- C Fleshy, sugar-rich fruits that attract birds
- D Hard, woody shells that float on water currents
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Answer: B. Wings, tufts of hair (pappus), or lightweight seeds
Why: Wind-dispersed seeds have adaptations: wings (maple, ash), pappus/tufts (dandelion, thistle), lightweight seeds. Travel long distances.
Q15.
The pollen tube grows from the stigma through the style to reach the:
- A Petal, where it deposits the male gametes
- B Nearest leaf, absorbing nutrients along the way
- C Ovule (for fertilization)
- D Root, traveling down through the vascular tissue
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Answer: C. Ovule (for fertilization)
Why: After landing on stigma, the pollen grain germinates and grows a pollen tube through the style to reach the ovule, delivering male gametes for fertilization.
Q16.
Parthenogenesis in plants (apomixis) refers to:
- A Fertilization occurring without any pollen transfer
- B Seed development without fertilization
- C Cloning achieved through tissue culture techniques
- D Vegetative propagation using only stem cuttings
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Answer: B. Seed development without fertilization
Why: Apomixis (plant parthenogenesis): seed/embryo development without fertilization. Produces genetically uniform plants. E.g., some grasses, dandelions.
Q17.
The embryo sac is the female gametophyte of angiosperms and contains:
- A 4 cells arranged symmetrically around one single, large central vacuole space
- B 6 cells, each one carrying a single diploid nucleus derived from the megaspore
- C 8 nuclei in 7 cells (including egg, two synergids, two polar nuclei, three antipodals)
- D Just the egg cell, surrounded entirely by several layers of sterile nucellus tissue
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Answer: C. 8 nuclei in 7 cells (including egg, two synergids, two polar nuclei, three antipodals)
Why: Mature embryo sac: 8 nuclei in 7 cells: 1 egg cell, 2 synergid cells, 1 central cell (2 polar nuclei), 3 antipodal cells.
Medium — 16 questions
Q18.
The mechanism of double fertilization in angiosperms produces:
- A Two separate embryos formed from two genetically independent egg cells within the ovule
- B One embryo (from egg + sperm) and endosperm (from central cell + second sperm)
- C One embryo alone, with the second sperm degenerating without ever being used
- D Two separate zygotes that later fuse together into a single diploid embryo
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Answer: B. One embryo (from egg + sperm) and endosperm (from central cell + second sperm)
Why: Double fertilization: sperm 1 + egg = 2n zygote (embryo); sperm 2 + two polar nuclei = 3n primary endosperm nucleus (nutritive endosperm).
Q19.
Pollen tube growth is directionally guided by:
- A Random diffusion through the stylar tissue matrix without any clear directional molecular cue present
- B Chemotropic signals from the ovule (LURE peptides secreted by synergid cells guide pollen tube)
- C Gravitropic sensing of the gravitational field acting specifically within the elongated style tissue
- D Wind direction sensed by specialized mechanoreceptors supposedly located at the pollen tube tip
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Answer: B. Chemotropic signals from the ovule (LURE peptides secreted by synergid cells guide pollen tube)
Why: Pollen tube guidance: LURE peptides (CRP proteins) from synergid cells of the embryo sac attract and guide the pollen tube through the style toward the micropyle of the ovule.
Q20.
Self-incompatibility (SI) in plants prevents self-fertilization by:
- A Physical separation of stamens and pistil onto entirely different flowers altogether
- B Molecular recognition between pollen and pistil S-gene products rejecting same-genotype pollen
- C Releasing volatile insect repellents that actively prevent pollinator visits to the flower
- D Producing no functional pollen grains whatsoever throughout anther development
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Answer: B. Molecular recognition between pollen and pistil S-gene products rejecting same-genotype pollen
Why: SI: stigma or pistil cells express S-gene products that recognize matching pollen S-alleles. If pistil and pollen share S alleles, pollen tube growth is inhibited, preventing inbreeding.
Q21.
Apomixis in plants is economically important because:
- A It is sometimes mistakenly thought to create considerably greater genetic diversity through frequent meiotic recombination as frequently observed in practice
- B It produces seeds without fertilization, allowing production of genetically uniform crops and fixing hybrid vigor across generations
- C It is sometimes mistakenly thought to increase disease resistance by introducing novel resistance alleles each generation in many documented cases
- D It is sometimes mistakenly thought to substantially accelerate the rate of spontaneous mutation within the genome according to conventional understanding
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Answer: B. It produces seeds without fertilization, allowing production of genetically uniform crops and fixing hybrid vigor across generations
Why: Apomixis: seed formation without fertilization. Produces genetically identical offspring. If introduced into crops, could fix hybrid vigor (heterosis) without costly hybrid seed production each year.
Q22.
In plant embryogenesis, the first asymmetric division of the zygote produces:
- A Two genetically identical daughter cells of exactly equal size and identical developmental fate each time in routine practice
- B A small apical cell (embryo proper) and large basal cell (suspensor that attaches to seed coat and nourishes embryo)
- C Endosperm tissue directly, largely bypassing the usual formation of the embryo proper itself overall in most cases
- D A largely formed multicellular embryo supposedly produced within just a single cell division event under typical conditions
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Answer: B. A small apical cell (embryo proper) and large basal cell (suspensor that attaches to seed coat and nourishes embryo)
Why: Zygote first division: asymmetric. Small apical cell → embryo proper (shoot/root meristems, cotyledons). Large basal cell → suspensor (anchors embryo, delivers nutrients).
Q23.
Wind-pollinated flowers (anemophilous) differ from insect-pollinated in having:
- A Large, brightly colored petals specifically evolved to attract pollinating insects from nearby areas according to standard textbooks
- B Small, inconspicuous flowers; large stigmas to catch pollen; copious, light, dry pollen; no nectaries or scent
- C Sweet nectar glands together with a strong, distinctive floral scent to attract visiting pollinators in general practice
- D Sticky pollen grains that are clumped together tightly in heavy, cohesive masses for insect transport as frequently described
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Answer: B. Small, inconspicuous flowers; large stigmas to catch pollen; copious, light, dry pollen; no nectaries or scent
Why: Wind-pollinated: small drab flowers (no need to attract insects), feathery or large stigmas to catch airborne pollen, abundant dry pollen released into wind, no nectar or scent.
Q24.
Polyembryony occurs in plants when:
- A More than one ovule matures and develops fully within a single ovary chamber simultaneously
- B Multiple embryos develop in one seed (from zygote, synergids, nucellus cells, or unfertilized egg)
- C Seeds are released from the mature fruit in tightly clustered groups all at the same time
- D A single flower develops several largely independent and separate pistils side by side
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Answer: B. Multiple embryos develop in one seed (from zygote, synergids, nucellus cells, or unfertilized egg)
Why: Polyembryony: multiple embryos in one seed. Examples: Citrus seeds. Can arise from additional zygotes, synergid cells, or nucellus cells developing into extra embryos (adventive embryony).
Q25.
The concept of alternation of generations in plants means:
- A Plants simply alternate between summer and winter growth phases each year
- B Diploid sporophyte and haploid gametophyte generations alternate in the life cycle
- C Plants alternate between sexual and asexual reproduction depending on the season
- D Different plant species gradually alternate dominance within a single ecosystem
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Answer: B. Diploid sporophyte and haploid gametophyte generations alternate in the life cycle
Why: Alternation of generations: diploid sporophyte (2n) produces haploid spores by meiosis. Spores germinate into haploid gametophyte (n) that produces gametes. Fertilization restores diploid sporophyte.
Q26.
Pollination by animals (zoophily) benefits plants because:
- A Animals actively consume and eliminate competing plant species growing nearby the flower over time under usual circumstances according to most researchers
- B Animals transfer pollen precisely between same species with high efficiency (compared to wind), especially via directed foraging behavior
- C Animals physically damage flowers during visits, which is sometimes thought to trigger a burst of pollen release in the majority of cases studied
- D Animals supply nitrogen-rich nutrients directly into the flower tissue during each visitation event as widely reported in standard practice
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Answer: B. Animals transfer pollen precisely between same species with high efficiency (compared to wind), especially via directed foraging behavior
Why: Zoophily: animals (bees, birds, bats) transfer pollen efficiently between same-species flowers. Flowers evolved attractive traits (color, scent, nectar) to reward and ensure reliable pollination.
Q27.
In heterosporous plants (like seed plants), microspores develop into:
- A Female gametophytes housed within the megasporangium
- B Male gametophytes (pollen grains containing the male gametes)
- C Sporophytes directly, bypassing the gametophyte generation
- D Embryos formed without any intervening fertilization step
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Answer: B. Male gametophytes (pollen grains containing the male gametes)
Why: Heterospory: two types of spores. Microspores (small) → male gametophyte (pollen grain). Megaspores (large) → female gametophyte (embryo sac). Evolved in seed plants.
Q28.
The nucellus in an ovule corresponds to:
- A The seed coat formed later from the hardened outer integument layers of the ovule
- B The megasporangium (diploid tissue surrounding and nourishing the megaspore/embryo sac)
- C The embryo that develops only after double fertilization of the egg has occurred
- D The endosperm tissue that forms from the fertilized central cell after fertilization
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Answer: B. The megasporangium (diploid tissue surrounding and nourishing the megaspore/embryo sac)
Why: Nucellus: the megasporangium of the seed plant ovule. Diploid tissue that surrounds the female gametophyte (embryo sac). Provides nutrients and physical support. Homologous to sporangium wall.
Q29.
Coevolution between flowers and pollinators is demonstrated by:
- A Flower shapes that vary largely at random with little underlying functional correlation overall under most conditions encountered
- B Morphological matching between flower structure and pollinator anatomy (orchid-bee coevolution, yucca-yucca moth mutualism)
- C Generalist pollinators that visit nearly every available flower species with little discrimination as frequently observed in practice
- D Plants that rely mainly on ambient wind currents for transferring pollen between flowers in many documented cases according to conventional understanding
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Answer: B. Morphological matching between flower structure and pollinator anatomy (orchid-bee coevolution, yucca-yucca moth mutualism)
Why: Flower-pollinator coevolution: plants and pollinators evolve together. Darwin predicted the Malagasy star orchid required a moth with 30 cm tongue to reach nectar -- confirmed 100 years later.
Q30.
Elaiosomes on seeds attract which seed dispersers?
- A Birds, which swallow the seeds whole and disperse them in droppings
- B Ants (myrmecochory -- ants carry seeds to their nests, dispersing them)
- C Wind currents that carry the lightweight seed structures
- D Water currents that float the seeds downstream
Show answer & explanation
Answer: B. Ants (myrmecochory -- ants carry seeds to their nests, dispersing them)
Why: Elaiosomes: lipid-rich seed appendages. Ants collect seeds for elaiosomes (food reward), carry them to nests, eat the elaiosome, and discard the viable seed -- dispersal by ants (myrmecochory).
Q31.
In vegetative propagation, micropropagation uses:
- A Seeds that have been collected specifically from selectively bred parent plant lines over generations under typical conditions
- B Tissue culture (callus formation from explants on hormone-containing media) to produce large numbers of clonal plants
- C Simple stem cuttings that are rooted directly in ordinary garden soil without any special treatment according to standard textbooks
- D Mainly bulbs and tubers that are planted directly into the field without any culturing process in general practice
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Answer: B. Tissue culture (callus formation from explants on hormone-containing media) to produce large numbers of clonal plants
Why: Micropropagation: plant explants (shoot tips, leaves) are cultured on media with auxin and cytokinin ratios controlling callus formation, shoot and root induction, producing thousands of clonal plants.
Q32.
Serotiny is a reproductive strategy where:
- A Seeds germinate almost immediately upon release from the parent plant with very little delay as frequently described in most textbook accounts
- B Seeds are stored in cones or fruits and released only after a specific trigger such as fire (e.g., lodgepole pine, Banksia)
- C Fruits develop and reach full maturity without any prior fertilization event ever taking place during normal conditions
- D Pollen is released from the anther mainly during the late nighttime hours specifically as generally observed in typical laboratory settings
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Answer: B. Seeds are stored in cones or fruits and released only after a specific trigger such as fire (e.g., lodgepole pine, Banksia)
Why: Serotiny: seeds sealed in fire-adapted cones or fruits (by resin). Fire melts resin, releasing seeds onto ash-enriched, competitor-free soil. Adaptation to fire-prone environments.
Q33.
The embryo of a monocot has how many cotyledons?
- A None, since monocot embryos lack cotyledon tissue entirely
- B One (single cotyledon called scutellum in grasses)
- C Two cotyledons fused together along the embryonic axis
- D Three to four cotyledons arranged around the plumule
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Answer: B. One (single cotyledon called scutellum in grasses)
Why: Monocots: one cotyledon (seed leaf). In grasses, it is the scutellum that absorbs nutrients from endosperm. Dicots have two cotyledons. This is a fundamental angiosperm classification.
Hard — 18 questions
Q34.
The gametophytic self-incompatibility system (GSI) in plants is controlled by:
- A Diploid sporophytic tissue of the pistil acting largely alone, without requiring much input from the pollen grain itself directly during normal conditions
- B Haploid pollen S-gene product interacting with pistil S-gene product; both encoded by multiallelic S-locus (e.g., RNase-based in Solanaceae)
- C The diploid seed coat tissue alone, acting mostly independently of any pollen-pistil molecular signaling interaction happening as generally observed
- D Epigenetic chromatin marks alone, occurring with little underlying genetic S-locus sequence ever being involved in practice in typical laboratory settings
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Answer: B. Haploid pollen S-gene product interacting with pistil S-gene product; both encoded by multiallelic S-locus (e.g., RNase-based in Solanaceae)
Why: GSI: pollen S-allele product determines incompatibility. In Solanaceae: S-RNase (pistil) degrades RNA in incompatible pollen tubes. In Papaveraceae: Ca2+ signaling inhibits pollen tube growth.
Q35.
Polyspermy is prevented in angiosperms by:
- A A simple physical size restriction at the narrow micropyle opening that permits only one pollen tube through at a time
- B Synergid cells sending signals to block subsequent pollen tube entry after the first tube enters and bursts
- C The developing endosperm tissue actively repelling any additional pollen tubes immediately after fertilization occurs
- D Specialized anti-pollen enzymes that are secreted directly by the egg cell cytoplasm itself before fertilization
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Answer: B. Synergid cells sending signals to block subsequent pollen tube entry after the first tube enters and bursts
Why: After first pollen tube enters synergid and bursts, the unfused synergid sends a rapid signal preventing other pollen tubes from entering. Mechanism involves changes in synergid and central cell signaling.
Q36.
Endosperm development in angiosperms can be:
- A Mainly cellular in most species, with rigid cell wall formation accompanying every nuclear division that occurs
- B Nuclear (nuclear divisions without walls), cellular (with walls), or helobial (in monocots) depending on species
- C Mainly liquid in form throughout development, rarely forming any solid cellular tissue structure whatsoever
- D Mainly starchy from the very beginning, largely lacking any free nuclear or true cellular developmental phase
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Answer: B. Nuclear (nuclear divisions without walls), cellular (with walls), or helobial (in monocots) depending on species
Why: Endosperm types: nuclear (free nuclear divisions in coconut liquid endosperm), cellular (walls after each division, as in many dicots), helobial (intermediate, common in monocots).
Q37.
Transcription factors MADS-box proteins in floral organ identity (ABC model) determine:
- A Leaf identity only, having absolutely no documented role whatsoever in determining the fate of any floral organ
- B Which floral organs form in which whorl (A genes: sepals/petals, B genes: petals/stamens, C genes: stamens/carpels)
- C Root system formation specifically through direct control over lateral root primordia initiation and emergence
- D Pollen tube growth rate and its precise chemotropic guidance pathway toward the awaiting ovule structure
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Answer: B. Which floral organs form in which whorl (A genes: sepals/petals, B genes: petals/stamens, C genes: stamens/carpels)
Why: ABC model of floral development: A alone = sepals; A+B = petals; B+C = stamens; C alone = carpels. MADS-box TFs (AP1, AP3/PI, AG) control floral organ identity in Arabidopsis.
Q38.
The CONSTANS (CO) protein promotes flowering in Arabidopsis by:
- A Directly activating the entire complete set of vegetative growth genes simultaneously, all at the exact same developmental time under usual circumstances
- B Activating FT (florigen) transcription in leaves only in long-day conditions when CO protein accumulates in the light (CO is degraded in dark by COP1)
- C Inhibiting gibberellin biosynthesis specifically within the actively dividing cells of the shoot apical meristem region according to most researchers
- D Directly triggering the onset of meiosis within developing reproductive cells of the flower, bypassing other key signals in the majority of cases studied
Show answer & explanation
Answer: B. Activating FT (florigen) transcription in leaves only in long-day conditions when CO protein accumulates in the light (CO is degraded in dark by COP1)
Why: CO protein: transcribed constitutively, but protein is rapidly degraded in dark by COP1 E3 ligase. In long days, CO accumulates in evening light, activating FT transcription. FT moves to apex to trigger flowering.
Q39.
Sporopollenin in pollen walls is resistant to:
- A Heat exposure alone, while showing essentially little resistance to either chemical or biological degradation processes occurring nearby naturally as widely reported in standard practice
- B Chemical degradation and biological attack (most powerful natural polymer), protecting pollen during transport -- only fluorescence microscopy and acetolysis can reveal patterns
- C Physical mechanical damage alone, while nevertheless remaining quite fragile and vulnerable to any chemical attack that occurs nearby under most conditions encountered as frequently observed in practice
- D UV radiation exposure alone, offering essentially little protection against any form of ongoing microbial degradation activity nearby in many documented cases according to conventional understanding
Show answer & explanation
Answer: B. Chemical degradation and biological attack (most powerful natural polymer), protecting pollen during transport -- only fluorescence microscopy and acetolysis can reveal patterns
Why: Sporopollenin: extraordinarily resistant biopolymer in exine (outer pollen wall). Resistant to acids, bases, oxidants, and most biological degradation. Preserved for millions of years in fossil record.
Q40.
Maternal effects on seed quality are due to:
- A Paternal DNA contributed mainly through the second sperm nucleus delivered during double fertilization, largely on its own in routine practice overall
- B The maternal plant providing nutrients, protective layers (testa from integuments), and imprinted genes that influence seed development and composition
- C Endosperm genes acting largely alone, mostly independent of any contribution from surrounding maternal tissue nearby in most cases under typical conditions
- D The single fertilization event occurring alone, largely without any meaningful contribution from maternal resources available according to standard textbooks
Show answer & explanation
Answer: B. The maternal plant providing nutrients, protective layers (testa from integuments), and imprinted genes that influence seed development and composition
Why: Maternal effects: seed coat (testa) is entirely maternal diploid tissue. Maternal plant provides nutrients via funicle. Maternal imprinting of some endosperm genes affects seed development and nutrient allocation.
Q41.
Recombinant inbred lines (RILs) are produced by:
- A Repeated self-incompatible crosses occurring between unrelated parent breeding lines over time
- B Repeated self-fertilization of F2 plants until homozygosity is ~99%, useful for QTL mapping
- C Backcrossing alone, without any intervening self-fertilization steps taking place
- D Vegetative cloning of a single heterozygous parent plant repeatedly over time
Show answer & explanation
Answer: B. Repeated self-fertilization of F2 plants until homozygosity is ~99%, useful for QTL mapping
Why: RILs: F2 plants are self-fertilized for 6-8 generations. Resulting lines are nearly 100% homozygous but carry a mosaic of the two parental genomes. Invaluable for QTL mapping and marker-assisted selection.
Q42.
The SEPALLATA (SEP) MADS-box genes are required in Arabidopsis for:
- A Root system development through specific control over the formation of lateral root primordia along the main root structure
- B Formation of any floral organs (in sep1 sep2 sep3 triple mutants, all organs become leaf-like despite functional ABC genes)
- C Pollen tube guidance alone, specifically directing tube growth toward the micropyle opening of the developing ovule
- D Seed dormancy mechanisms that are regulated largely independently of any floral organ identity gene activity present
Show answer & explanation
Answer: B. Formation of any floral organs (in sep1 sep2 sep3 triple mutants, all organs become leaf-like despite functional ABC genes)
Why: SEP genes (SEP1-4): essential cofactors for floral homeotic MADS proteins. Without SEP, ABC proteins cannot form active tetrameric complexes. All organs revert to leaf-like structures in sep triple mutants.
Q43.
Hybrid seed production requires male sterility in the seed parent. CMS (cytoplasmic male sterility) is:
- A A nuclear recessive mutation that is inherited generally according to standard Mendelian segregation ratios across generations
- B Sterility caused by mitochondrial genes that prevent pollen development (used in hybrid seed production in rice, maize, sorghum)
- C A condition that is caused specifically by deletion of particular genes located on the X chromosome itself
- D A condition induced largely by a persistent, latent viral infection that specifically targets the developing anther tissue
Show answer & explanation
Answer: B. Sterility caused by mitochondrial genes that prevent pollen development (used in hybrid seed production in rice, maize, sorghum)
Why: CMS: mitochondrial gene (non-Mendelian) causes pollen abortion. Nuclear restorer genes (Rf) can restore fertility. Used in F1 hybrid seed production: CMS female x normal male -- no manual emasculation needed.
Q44.
In conifer reproduction, the pollen grain germinates and the pollen tube grows for:
- A Just a few hours typically pass before fertilization is fully completed
- B Days to months (up to 12 months in some species) before fertilization occurs
- C Mainly a matter of seconds pass before the egg becomes fertilized
- D A fixed period of exactly two weeks occurs in every conifer species studied
Show answer & explanation
Answer: B. Days to months (up to 12 months in some species) before fertilization occurs
Why: Conifers: after wind pollination, pollen tube grows slowly through female gametophyte tissue. In Pinus, this takes ~12 months. The tube eventually delivers sperm cells to the archegonium for fertilization.
Q45.
The endosperm balance number (EBN) concept explains:
- A Endosperm size alone, with little reference to underlying hybrid genetic compatibility between species involved in general practice as frequently described
- B Why interspecific hybrids often fail due to imbalanced maternal:paternal genomic contributions to endosperm (2m:1p required), controlled by imprinted genes
- C How starch granules are synthesized and subsequently packaged within the developing endosperm tissue structure itself in most textbook accounts during normal conditions
- D Embryo dormancy mechanisms that are triggered largely independently of any underlying endosperm genetic factor present as generally observed in typical laboratory settings
Show answer & explanation
Answer: B. Why interspecific hybrids often fail due to imbalanced maternal:paternal genomic contributions to endosperm (2m:1p required), controlled by imprinted genes
Why: EBN (Endosperm Balance Number, Johnston): endosperm requires 2 maternal:1 paternal genome contributions (2:1 ratio). Imprinted genes in endosperm control this. Wrong ratio causes endosperm failure and hybrid inviability.
Q46.
The use of embryo rescue in plant breeding allows:
- A Regenerating embryos that have already been largely lost from otherwise mature, largely developed seed tissue structures under usual circumstances
- B Saving hybrid embryos that would otherwise abort due to genetic incompatibility by culturing excised embryos on artificial medium
- C Cloning plants considerably more rapidly than would be possible through conventional vegetative propagation methods alone according to most researchers
- D Producing polyploid plants mainly, with few other documented breeding applications existing for this particular technique in the majority of cases studied
Show answer & explanation
Answer: B. Saving hybrid embryos that would otherwise abort due to genetic incompatibility by culturing excised embryos on artificial medium
Why: Embryo rescue: in wide crosses between species, endosperm often fails (EBN mismatch, incompatible maternal signals). Immature embryos excised and cultured in vitro before abortion, recovering viable hybrid plants.
Q47.
Pollen competition refers to:
- A Direct competition occurring specifically between male and female flowers located on the very same individual plant species as widely reported in standard practice
- B Multiple pollen grains competing to fertilize the egg -- pollen with superior competitive ability (faster tube growth) selected, potentially improving offspring fitness
- C Pollen grains competing directly against fern spores for occupation of the exact same ecological niche space available under most conditions encountered as frequently observed in practice
- D Competition that occurs mainly between different plant species when attracting the same shared pollinator visitors nearby in many documented cases according to conventional understanding
Show answer & explanation
Answer: B. Multiple pollen grains competing to fertilize the egg -- pollen with superior competitive ability (faster tube growth) selected, potentially improving offspring fitness
Why: Pollen competition: when many pollen grains germinate on a stigma, faster or more vigorous pollen tubes are more likely to fertilize the egg. May select for superior gametes, increasing offspring quality.
Q48.
In angiosperm evolution, the endosperm may have evolved as:
- A A largely protective structure that serves little functional role in nutrient allocation toward the developing embryo overall in routine practice overall in most cases
- B A mechanism for maternal resource control over offspring -- endosperm is a battleground between maternal and paternal genomes for resource allocation (imprinting conflicts)
- C Mainly a food storage tissue, with little underlying genomic conflict of any kind being involved in its actual formation under typical conditions according to standard textbooks
- D An immune defense system specifically evolved mainly to protect the developing seed from pathogen and pest attack in general practice as frequently described in most textbook accounts
Show answer & explanation
Answer: B. A mechanism for maternal resource control over offspring -- endosperm is a battleground between maternal and paternal genomes for resource allocation (imprinting conflicts)
Why: Genomic imprinting in endosperm is explained by the kinship theory (Haig): maternal genome favors equal allocation; paternal genome favors more resource to that seed. Paternally imprinted FIS genes vs maternally imprinted MEA regulate endosperm growth.
Q49.
Heterostyly (e.g., in Primula) prevents self-pollination by:
- A Having largely separate male and female plants existing individually within the same breeding population in general practice as frequently described
- B Having morphologically distinct flower types (pin and thrum) where stamens of one type are at the same height as stigma of other type, promoting cross-pollination
- C Relying mainly upon chemical self-incompatibility reactions occurring specifically at the receptive stigma surface itself in most textbook accounts during normal conditions
- D Temporal separation occurring mainly between the timing of pollen release and the period of stigma receptivity, as observed in typical laboratory settings
Show answer & explanation
Answer: B. Having morphologically distinct flower types (pin and thrum) where stamens of one type are at the same height as stigma of other type, promoting cross-pollination
Why: Heterostyly (distyly/tristyly): flowers differ in position of stamens and stigma. Pin (long style, low anthers) x Thrum (short style, high anthers) ensures pollen lands on stigma of opposite type -- mechanical self-incompatibility.
Q50.
Seed banks use cryopreservation and control seed moisture to:
- A Increase the overall rate of seed germination immediately upon subsequent planting under typical field growing conditions each season during normal conditions as generally observed
- B Preserve genetic diversity of plant species for thousands of years by slowing metabolism to near zero in liquid nitrogen or at -20 to -18 degrees C with low moisture content
- C Preserve mainly commercially important agricultural crop varieties, while largely excluding most wild relative species nearby in typical laboratory settings under usual circumstances
- D Store seeds in a state that is immediately ready for planting and rapid germination without requiring any further preparation steps taken according to most researchers
Show answer & explanation
Answer: B. Preserve genetic diversity of plant species for thousands of years by slowing metabolism to near zero in liquid nitrogen or at -20 to -18 degrees C with low moisture content
Why: Seed banks (e.g., Svalbard Global Seed Vault): reduce seed moisture to 5-7% and store at -18 to -20 C (or cryopreservation in liquid N2). Metabolic activity essentially halted; viability maintained for decades to centuries.
Q51.
Transgenerational epigenetic inheritance in plants occurs when:
- A Permanent changes to the underlying DNA sequence itself are sometimes thought to be passed directly on to the resulting offspring generation each time
- B Epigenetic marks (methylation, chromatin states) established in response to stress are transmitted through seeds to offspring, influencing their phenotype
- C The underlying gene sequences themselves are sometimes thought to undergo permanent change specifically within the offspring generation by itself
- D Mainly small interfering RNA molecules are sometimes thought to be inherited, with little chromatin or methylation marks being involved
Show answer & explanation
Answer: B. Epigenetic marks (methylation, chromatin states) established in response to stress are transmitted through seeds to offspring, influencing their phenotype
Why: Transgenerational epigenetic inheritance: stress-induced chromatin changes (DNA methylation, small RNA) can persist through meiosis and be inherited by offspring. Plants may be primed for same stress. Less erased than in animals.