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Morphology of Flowering Plants — Practice Questions with Answers

13 free MCQs on Morphology of Flowering Plants with worked answers and explanations. External structure of roots, stems, and leaves plus internal tissue organization. High marks in Class 11 and NEET.

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Below are 13 practice questions on Morphology of Flowering Plants, sorted Easy → Hard. Tap “Show answer & explanation” under any question to check yourself. Want the full theory first? Read the Morphology of Flowering Plants notes.

Stem Cross-Section: Dicot vs MonocotDicot: bundles in a RINGMonocot: bundles SCATTERED

In a dicot stem, vascular bundles are arranged in a single ring (with cambium between xylem and phloem, enabling secondary growth); in a monocot stem, bundles are scattered throughout with no cambium, so monocots can't undergo secondary growth (no wood formation).

Easy — 8 questions

Q1.

What is the tap root system?

  • A Many roots of equal size from stem base
  • B A main primary root with lateral branches
  • C Root that stores food only
  • D Root found in grasses
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Answer: B. A main primary root with lateral branches

Why: A tap root system has a single main primary root that grows downward with lateral branch roots. It is characteristic of dicotyledons like carrot, radish, and sunflower.

Q2.

Which modification of the stem is found in potato?

  • A Rhizome
  • B Corm
  • C Tuber
  • D Bulb
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Answer: C. Tuber

Why: Potato is a stem tuber - a swollen underground stem that stores food. The 'eyes' on potatoes are nodes with axillary buds, confirming it is a modified stem, not a root.

Q3.

Leaves with net-like veins are called

  • A Parallel venation
  • B Reticulate venation
  • C Alternate venation
  • D Simple venation
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Answer: B. Reticulate venation

Why: Reticulate (net-like) venation is characteristic of dicotyledonous leaves. The veins form an interconnected network. Monocots have parallel venation.

Q4.

Ginger is a modified underground stem called a

  • A Bulb
  • B Corm
  • C Rhizome
  • D Tuber
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Answer: C. Rhizome

Why: Ginger is a rhizome - a horizontal underground stem that stores food. It has nodes, internodes, scale leaves, and buds. Other examples: turmeric, lotus, fern.

Q5.

Simple leaves differ from compound leaves in that

  • A Simple leaves have many more leaflets per node
  • B Simple leaves have a single, undivided lamina
  • C Simple leaves show very little visible venation across the blade
  • D Simple leaves fall off much faster each season
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Answer: B. Simple leaves have a single, undivided lamina

Why: A simple leaf has a single, undivided leaf blade (lamina). A compound leaf has the blade divided into leaflets. Examples: simple - mango, banyan; compound - rose, neem, pea.

Q6.

Onion is an example of which stem modification?

  • A Rhizome
  • B Tuber
  • C Corm
  • D Bulb
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Answer: D. Bulb

Why: Onion is a bulb - a modified underground stem with a short stem base bearing fleshy scale leaves (modified leaves) that store food. Other examples: garlic, tulip, lily.

Q7.

The arrangement of leaves on a stem is called

  • A Phyllotaxy
  • B Venation
  • C Aestivation
  • D Vernation
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Answer: A. Phyllotaxy

Why: Phyllotaxy refers to the arrangement of leaves on the stem. Types include alternate (one leaf per node), opposite (two leaves per node), and whorled (more than two per node).

Q8.

Which part of the stem is between two nodes?

  • A Axil
  • B Internode
  • C Petiole
  • D Lamina
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Answer: B. Internode

Why: An internode is the stem segment between two nodes. Nodes are points where leaves, branches, or flowers arise. Internodes vary in length and are elongated in bamboo.

Medium — 5 questions

Q9.

Thorn of Bougainvillea is an example of which stem modification?

  • A Stem tendril
  • B Stem spine (thorn)
  • C Phylloclade
  • D Cladode
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Answer: B. Stem spine (thorn)

Why: Bougainvillea has stem modifications into hard, sharp thorns (spines) that are modified axillary buds or stems. They provide defense. Contrast with leaf-spine (cactus) and prickle (rose - epidermal outgrowth).

Q10.

What distinguishes a fibrous root system advantage in soil erosion prevention?

  • A Tap roots penetrate much deeper, anchoring the plant firmly against strong winds
  • B Fibrous roots spread wide and shallow, binding topsoil and preventing erosion better
  • C Tap roots and fibrous roots are considered roughly equally effective at binding topsoil
  • D Fibrous roots tend to develop mainly in consistently moist, well-irrigated soil conditions
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Answer: B. Fibrous roots spread wide and shallow, binding topsoil and preventing erosion better

Why: Fibrous root systems spread extensively near the soil surface, binding topsoil particles and preventing soil erosion by wind and water. Grasses are particularly effective ground cover plants for this reason.

Q11.

What is lenticel?

  • A A specialized parenchyma cell found within the leaf mesophyll
  • B A pore in bark for gas exchange in woody stems
  • C A guard-cell structure derived from a modified stoma
  • D A thin tubular extension forming a root hair
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Answer: B. A pore in bark for gas exchange in woody stems

Why: Lenticels are small pores in the bark (periderm) of woody plants that allow gas exchange between internal tissues and the atmosphere, replacing stomata which are covered by bark.

Q12.

What is a phylloclade?

  • A A modified adventitious root specially adapted for climbing surfaces and structures
  • B A flattened, photosynthetic stem that resembles a leaf, found in Opuntia (cactus)
  • C A swollen underground bulb specially adapted for storing food during dormancy
  • D A spine-like modified leaf adapted mainly for defense against herbivores
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Answer: B. A flattened, photosynthetic stem that resembles a leaf, found in Opuntia (cactus)

Why: A phylloclade is a flattened, green, photosynthetic stem that performs leaf functions. Found in Opuntia (cactus) and Casuarina. The true leaves are reduced to spines or scales to reduce water loss in dry habitats.

Q13.

What is a bulbil?

  • A A type of fleshy, starch-storing underground root, similar in form to a sweet potato
  • B A small bulb-like structure that functions as a vegetative propagule (asexual reproduction)
  • C A modified leaf-like floral bract that surrounds and protects the developing flower bud
  • D A small leaf-like stipule appendage attached firmly at the base of the leaf petiole
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Answer: B. A small bulb-like structure that functions as a vegetative propagule (asexual reproduction)

Why: Bulbils are small, fleshy, vegetative buds that fall from the parent plant and germinate to form new individuals. Found in Agave (leaf bulbils), Oxalis (stem bulbils), and some lilies. They represent vegetative propagation.