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The Bohr effect explains why hemoglobin releases O<sub>2</sub> in metabolically active tissues. Which factors cause this?

Answer: High CO 2 and low pH.

  • A High O<sub>2</sub> and low CO<sub>2</sub>
  • B Low CO<sub>2</sub> and high pH
  • C High CO<sub>2</sub> and low pH
  • D High pH and low temperature

Correct answer: C. High CO<sub>2</sub> and low pH

Explanation: The Bohr effect: high CO<sub>2</sub> (lowers pH by forming carbonic acid) and high H+ decrease hemoglobin affinity for O<sub>2</sub>. This promotes O<sub>2</sub> release in active tissues where CO<sub>2</sub> is produced.

Enzyme Kinetics: Rate vs Substrate Concentration[Substrate]Reaction rateVmaxKm½VmaxCurve flattens at high [S]: ALL enzyme active sites are occupied (saturation)

As substrate concentration rises, reaction rate increases steeply at first, then plateaus at Vmax once every enzyme molecule is working at full capacity; Km is the substrate concentration giving half-maximal rate, and a LOWER Km means the enzyme reaches that rate with less substrate (higher affinity).

Concept context

Carbohydrates, proteins, lipids, nucleic acids, and enzyme kinetics. Essential foundation for understanding metabolism.

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