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Dual Nature of Radiation and Matter

Photoelectric effect, de Broglie waves, Bohr's model, atomic spectra.

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Reading time~7 min
Revision time~2 min
Last updated2026-07-19
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🎯 Key Points

  • Photoelectric effect: KE_max=hf−φ=h(f−f₀); below threshold frequency f₀, NO electrons emitted regardless of intensity (proves particle nature of light)
  • Stopping potential eV₀=KE_max — depends only on frequency, NOT intensity (intensity only affects number of photoelectrons/current)
  • de Broglie wavelength: λ=h/p=h/mv — applies to ALL matter, not just electrons
  • Bohr model: mvr=nh/2π; E_n=−13.6/n² eV; r_n=n²a₀; ionization energy from ground state = 13.6 eV
  • Spectral series: Lyman (UV, transitions to n=1), Balmer (visible, to n=2), Paschen (IR, to n=3)

Photoelectric Effect

evacuated tubelightmetal platee⁻e⁻e⁻collectorAbattery (variable)

In the photoelectric setup, light striking the metal plate ejects electrons that cross the evacuated tube to the collector, producing a measurable current on the ammeter.

  • Einstein's explanation: E = hf (photon energy)
  • Work function: φ = hf₀ (minimum energy to eject electron)
  • KE_max = hf - φ = h(f - f₀)
  • Stopping potential: eV₀ = KE_max
  • Millikan's experiment: confirmed Einstein's photon theory
Graph of maximum photoelectron energy in electronvolts against incident light frequency for caesium, zinc and silver: three parallel straight lines of identical slope h, each cutting the frequency axis at its own threshold frequency and the energy axis at minus its work function, with the visible band shaded

Einstein’s photoelectric equation E = hf − φ: the lines are parallel (common slope h), and each metal has its own threshold frequency and work function. Decimal commas are the European convention (10,4 means 10.4). Image: Klaus-Dieter Keller, MikeRun, CC BY 3.0, via Wikimedia Commons.

de Broglie Waves

  • λ = h/p = h/mv (matter waves)
  • Davisson-Germer experiment: confirmed wave nature of electrons

Bohr's Model of Hydrogen

+n=1n=2n=3e⁻photon emittedn=1 (-13.6 eV)n=2 (-3.4 eV)n=3 (-1.5 eV)n=∞ (0 eV)

In Bohr's model, electrons occupy fixed circular orbits around the nucleus; a transition to a lower orbit releases a photon whose energy equals the difference between energy levels.

  • Quantization: mvr = nh/2π (angular momentum)
  • Orbit radii: r_n = n²a₀ (a₀ = 0.529 Å = Bohr radius)
  • Energy levels: E_n = -13.6/n² eV
  • Ground state: E₁ = -13.6 eV; ionization energy = 13.6 eV
  • Spectral series: Lyman (UV), Balmer (visible), Paschen (IR)

Electron Emission and Work Function

  • Free electrons inside a metal are held in by an attractive surface barrier; the minimum energy needed to just free an electron from the surface is the work function φ (a few eV, e.g. ~2.3 eV for sodium, ~4.5 eV for tungsten)
  • Thermionic emission: electrons freed by heating the metal (used in cathode-ray and vacuum tubes)
  • Field (cold) emission: electrons pulled out by applying a very strong external electric field
  • Photoelectric emission: electrons ejected when light of suitable frequency is incident on the surface
  • Secondary emission: electrons knocked out by the impact of fast-moving electrons or other particles

Photoelectric Effect: Early Observations

  • Hertz (1887): while producing electromagnetic waves, noticed that ultraviolet light falling on a metal electrode eased the discharge across a spark gap
  • Hallwachs and Lenard: showed that a negatively charged zinc plate lost its charge when illuminated with UV light while a positively charged plate did not, proving negative particles (electrons) were being emitted
  • Emission occurred only when the incident light frequency exceeded a certain minimum threshold frequency f₀, characteristic of the metal
  • The ejected electrons are called photoelectrons and the resulting current the photoelectric current

Experimental Study of the Photoelectric Effect

  • Effect of intensity (frequency fixed, above threshold): the photoelectric current, and hence the number of photoelectrons emitted per second, is directly proportional to the intensity of the light
  • Effect of potential: the current rises with the accelerating collector potential until it reaches a constant saturation current; a reverse (negative) potential reduces the current, and at the stopping potential V₀ even the fastest electrons are turned back so the current falls to zero
  • Effect of frequency: the stopping potential, and hence KE_max of the photoelectrons, increases linearly with frequency but is independent of intensity; below f₀ no emission occurs however intense the light
  • Emission is practically instantaneous (within ~10⁻⁹ s) with no time lag even at very low intensity — impossible to explain on the wave theory of light

Particle Nature of Light: The Photon

  • Einstein (1905) proposed that light energy is carried in discrete packets called photons, each of energy E = hf and momentum p = hf/c = h/λ
  • A photon has zero rest mass, travels at speed c, and is electrically neutral; its energy and momentum are fixed by the frequency of the radiation
  • In a photon-electron collision the total energy and momentum are conserved; intensity corresponds to the number of photons crossing unit area per second, not to the energy of an individual photon
  • This particle picture explains the threshold frequency, the instantaneous emission, and why KE_max depends on frequency but not intensity — resolving every puzzle of the photoelectric effect

Wave Nature of Matter and the Davisson-Germer Experiment

  • de Broglie (1924) proposed that all moving matter has an associated wavelength λ = h/p = h/mv; this wave nature is significant only for very small particles such as electrons because h is extremely small
  • For an electron accelerated through a potential V: λ = h/√(2meV) ≈ 1.227/√V nm (with V in volts)
  • Davisson-Germer experiment (1927): a beam of electrons accelerated through ~54 V was scattered from a nickel crystal; a pronounced peak in scattered intensity at 50° matched the de Broglie wavelength predicted by diffraction, confirming the wave nature of electrons
  • Electron diffraction is direct experimental proof of matter waves and underlies the working of the electron microscope

🚀 JEE Advanced Edge

Photoelectric stopping potential graphs: A graph of stopping potential V₀ vs frequency f is a straight line with slope h/e (giving a way to experimentally determine Planck's constant) and x-intercept at the threshold frequency f₀ — a very common JEE graph-reading question.

de Broglie wavelength of charged particles after acceleration: For a charge q accelerated through potential V, λ=h/√(2mqV) — note this differs from the electron-only version by replacing e with the general charge q, important for proton/alpha-particle de Broglie problems.

Worked problem: Find the de Broglie wavelength of an electron accelerated through a potential difference of 100V. Approach: λ=h/√(2meV) = (6.63×10⁻³⁴)/√(2×9.1×10⁻³¹×1.6×10⁻¹⁹×100) ≈ 1.23×10⁻¹⁰ m = 1.23 Å.

2 Revise ~2 min before the exam

📐 Formula Sheet

  • Photon energy: E = hν = hc/λ, with h = 6.63 × 10⁻³⁴ J·s
  • Photon momentum: p = h/λ = E/c
  • Einstein's photoelectric equation: hν = φ₀ + KEmax
  • Work function: φ₀ = hν₀ = hc/λ₀ (threshold frequency/wavelength)
  • Stopping potential: eV₀ = KEmax = hν − φ₀
  • de Broglie wavelength: λ = h/p = h/mv  |  in terms of KE: λ = h/√(2mKE)
  • Electron accelerated through V: λ = 12.27/√V Å
  • Useful shortcut: E(eV) = 12400/λ(Å)
3 Practice apply it

✍️ Worked Examples

Example 1 — Photoelectric effect
Q: Light of wavelength 4000 Å falls on a metal of work function 2 eV. Find the maximum kinetic energy of the photoelectrons.
Step 1 — Photon energy via the shortcut: E = 12400/4000 = 3.1 eV.
Step 2 — Einstein's equation: KEmax = E − φ₀.
Step 3 — Substitute: KEmax = 3.1 − 2 = 1.1 eV.
Answer: 1.1 eV, so the stopping potential is 1.1 V. Key idea: increasing the intensity raises the number of electrons, never their maximum energy — only frequency does that.

Example 2 — Threshold wavelength
Q: A metal has a work function of 3.1 eV. Find its threshold wavelength, and state whether 5000 Å light will eject electrons.
Step 1 — Threshold: λ₀ = 12400/φ₀(eV) = 12400/3.1 = 4000 Å.
Step 2 — Compare: the incident light is 5000 Å, which is longer than 4000 Å.
Step 3 — Longer wavelength means lower energy (E = hc/λ), so it falls below the threshold.
Answer: λ₀ = 4000 Å; 5000 Å light ejects no electrons, no matter how intense.

Example 3 — de Broglie wavelength of an electron
Q: An electron is accelerated through 100 V. Find its de Broglie wavelength.
Step 1 — Use the standard result: λ = 12.27/√V Å.
Step 2 — Substitute: λ = 12.27/√100 = 12.27/10.
Step 3 — Compute: λ = 1.227 Å.
Answer: ≈ 1.23 Å. Note: this is comparable to atomic spacing in crystals, which is exactly why electron diffraction works and confirms matter waves.

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Frequently Asked Questions — Dual Nature of Radiation and Matter

What are the key concepts in Dual Nature of Radiation and Matter?
Photoelectric effect, de Broglie waves, Bohr's model, atomic spectra.
Is Dual Nature of Radiation and Matter important for NEET & JEE?
Yes. Dual Nature of Radiation and Matter is part of the Physics Class 12 NCERT syllabus and is directly tested in NEET and JEE examinations. StudyHub provides structured notes, diagrams, and practice questions covering all exam-level subtopics.
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References

  1. NCERT Class 12 Physics Textbook — Chapter: Dual Nature of Radiation and Matter
  2. CBSE Curriculum — Physics (Class 12)
  3. NTA NEET UG Official Syllabus — subject-wise topic list
  4. NTA JEE Main Official Syllabus — subject-wise topic list