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Statistics

Mean, median, mode, standard deviation, and data interpretation

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Reading time~8 min
Revision time~3 min
Last updated2026-07-17
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🎯 Key Points

  • Empirical relation: Mode = 3·Median − 2·Mean — lets you find any ONE of the three if the other two are known, without recomputing from raw data
  • Step-deviation method (Mean = A+h·Σfu/Σf) avoids large-number arithmetic for grouped data — same final answer as the direct method, just easier computation
  • Standard deviation is ALWAYS non-negative and uses every data point (unlike range, which only uses the two extremes) — the most reliable single measure of spread
  • Coefficient of Variation (CV=σ/x̄×100%) compares variability across datasets with DIFFERENT means/units — lower CV means more consistent, even if the raw σ values aren't directly comparable
Normal Distribution: the 68-95-99.7 Rule68% within ±1σ95% within ±2σmean=median=mode (centre)

In a perfectly normal (bell-shaped) distribution, mean, median, and mode all coincide at the centre; about 68% of data falls within 1 standard deviation of the mean, 95% within 2, and 99.7% within 3 — the empirical rule used to judge how typical or extreme a value is.

Statistics & Data Analysis

Statistics is the science of collecting, organizing, analyzing, and interpreting numerical data.

Measures of Central Tendency

  • Mean (Arithmetic Mean): x̄ = (Σfx) / (Σf); for grouped data use midpoints
  • Median: Middle value of ordered data; for grouped: Median = l + [(n/2 - F)/f] × h
  • Mode: Most frequent value; for grouped: Mode = l + [f₁-f₀ / 2f₁-f₀-f₂] × h
  • Relation: Mode = 3 Median - 2 Mean (empirical)

Measures of Dispersion

  • Range: Maximum - Minimum
  • Variance: σ² = Σf(x-x̄)² / Σf
  • Standard deviation: σ = √variance
  • Coefficient of variation: CV = (σ/x̄) × 100%; used to compare variability
  • Mean deviation: Σ|x - central value| / n
  • Quartiles: Q1 (25th percentile), Q3 (75th percentile), IQR = Q3 - Q1

Types of Data Representation

  • Bar graph, pie chart, histogram (no gaps), frequency polygon, ogive (cumulative frequency curve)
  • Stem-and-leaf plot, box plot (five-number summary)

Correlation and Regression

  • Correlation coefficient r: -1 ≤ r ≤ 1; r = 1 perfect positive, r = -1 perfect negative, r = 0 no correlation
  • Line of best fit (regression line): y = a + bx where b = Σ(x-x̄)(y-ȳ)/Σ(x-x̄)²

Normal Distribution

  • Bell-shaped, symmetric about mean
  • 68-95-99.7 rule: 68% within ±1σ, 95% within ±2σ, 99.7% within ±3σ

Worked Example: Mean by the Step-Deviation Method

For grouped data, the step-deviation (shortcut) method avoids large numbers by using u = (x - A)/h, where A is an assumed mean and h is the class width:

Mean = A + h x (Σfu / Σf)

Consider class intervals 0-10, 10-20, 20-30, 30-40, 40-50 with frequencies 5, 8, 15, 16, 6 (N = 50) and midpoints 5, 15, 25, 35, 45. Taking A = 25 and h = 10, the deviations u are -2, -1, 0, 1, 2.

Σfu = 5(-2) + 8(-1) + 15(0) + 16(1) + 6(2) = -10 - 8 + 0 + 16 + 12 = 10.

Mean = 25 + 10 x (10/50) = 25 + 2 = 27. This matches the direct method (Σfx/N), but with much smaller numbers to handle.

Worked Example: Variance by the Shortcut Method

Using the same data, variance by the step-deviation method is σ^2 = h^2 x [(Σfu^2/N) - (Σfu/N)^2].

Σfu^2 = 5(4) + 8(1) + 15(0) + 16(1) + 6(4) = 20 + 8 + 0 + 16 + 24 = 68.

σ^2 = 100 x [(68/50) - (10/50)^2] = 100 x [1.36 - 0.04] = 100 x 1.32 = 132.

Standard deviation σ = sqrt(132) ≈ 11.49. This is exactly what the direct method Σf(x - xbar)^2/N would also give, confirming the shortcut formula.

Variance and SD by the Direct Method (Ungrouped Data)

  • Variance: σ^2 = (Σ(x - xbar)^2) / n
  • Standard deviation: σ = sqrt(σ^2)
  • Shortcut formula avoiding the mean subtraction step: σ^2 = (Σx^2/n) - (Σx/n)^2
  • Tip: Standard deviation is always non-negative, and it is the most reliable measure of dispersion since it uses every data point, unlike range which only uses the extremes.

Using Coefficient of Variation to Compare Two Datasets

CV = (σ/xbar) x 100% lets you compare the relative variability of two datasets even when their means are very different (for example, comparing the consistency of marks in two subjects with different maximum scores). The dataset with the lower CV is considered more consistent or less variable.

Mean Deviation about the Mean and Median

Mean deviation measures dispersion as the average of the absolute distances of the observations from a central value, so it is never negative.

  • About the mean: M.D.(x̄) = Σfᵢ|xᵢ - x̄| / N (for ungrouped data all fᵢ = 1, so it is Σ|xᵢ - x̄|/n).
  • About the median: M.D.(M) = Σfᵢ|xᵢ - M| / N.
  • The mean deviation is least when taken about the median — no other point gives a smaller average absolute deviation.
  • Coefficient of mean deviation = M.D. ÷ (the central value used), useful for comparing dispersion across datasets.

Worked example: for the data 4, 7, 8, 9, 10, 12, 14 (n = 7) the mean is 64/7 ≈ 9.14 and the median is 9. Mean deviation about the median = (|4-9|+|7-9|+|8-9|+|9-9|+|10-9|+|12-9|+|14-9|)/7 = (5+2+1+0+1+3+5)/7 = 17/7 ≈ 2.43.

Range, Quartile Deviation, and Their Coefficients

  • Range = Largest value (L) - Smallest value (S); Coefficient of range = (L - S)/(L + S).
  • Quartile deviation (semi-interquartile range) = (Q₃ - Q₁)/2; Coefficient of quartile deviation = (Q₃ - Q₁)/(Q₃ + Q₁).
  • Range uses only the two extreme values, while quartile deviation ignores the extreme 25% at each end, making it more resistant to outliers than the range.

Choosing Between Mean, Median, and Mode

  • The mean uses every observation and is best for symmetric data, but it is pulled toward extreme values (outliers).
  • The median depends only on the middle position, so it is the preferred average for skewed data or when outliers are present (e.g. incomes).
  • The mode is the only average usable for purely categorical data and identifies the most typical or most frequent value.
  • For a symmetric distribution mean = median = mode; for a right-skewed distribution mean > median > mode, and the order reverses for left skew.

🚀 JEE Advanced Edge

Why variance is NOT additive under a linear transformation in the obvious way: If Y=aX+b, then Var(Y)=a²·Var(X) — the additive constant b shifts the mean but doesn't affect spread at all (Var unaffected by b), while the multiplicative constant a scales the variance by a² (not a) because variance involves SQUARED deviations. This "shift doesn't matter, scale squares" rule resolves a huge class of "find the new variance after transformation" problems instantly.

Effect of combining datasets on the combined mean and variance: If two datasets have n₁, n₂ observations with means x̄₁, x̄₂, the combined mean is the WEIGHTED average (n₁x̄₁+n₂x̄₂)/(n₁+n₂), NOT the simple average of the two means — this weighting by sample size is essential whenever group sizes differ and is a common error source in board/JEE-adjacent problems.

Worked problem: A dataset has variance 16. If every value in the dataset is multiplied by 3 and then increased by 5, find the new variance. Approach: Y=3X+5, so Var(Y)=3²·Var(X)=9×16=144. (The "+5" shift has zero effect on variance.)

2 Revise ~3 min before the exam

📐 Formula Sheet

  • Mean: x̄ = Σx/n  |  grouped: x̄ = Σf·x/Σf
  • Median (grouped): l + [(n/2 − cf)/f]·h
  • Mode (grouped): l + [(f₁ − f₀)/(2f₁ − f₀ − f₂)]·h
  • Empirical relation: Mode = 3·Median − 2·Mean
  • Variance: σ² = Σ(x − x̄)²/n = (Σx²/n) − x̄²
  • Standard deviation: σ = √(variance)
  • Coefficient of variation: CV = (σ/x̄) × 100 — the standard tool for comparing consistency
  • Effect of change: adding a constant shifts the mean but not σ; multiplying by k scales both the mean and σ by k
3 Practice apply it

✍️ Worked Examples

Example 1 — Mean and standard deviation
Q: Find the mean and standard deviation of 2, 4, 6, 8, 10.
Step 1 — Mean: (2 + 4 + 6 + 8 + 10)/5 = 30/5 = 6.
Step 2 — Squared deviations: 16, 4, 0, 4, 16, summing to 40.
Step 3 — Variance: 40/5 = 8, so σ = √8 ≈ 2.83.
Answer: mean 6, σ ≈ 2.83. Note: the deviations are symmetric about the mean, as they must be.

Example 2 — Comparing consistency
Q: Team A averages 50 with σ = 5; team B averages 80 with σ = 5. Which is more consistent?
Step 1 — Equal σ does not settle it, because the means differ — use the coefficient of variation.
Step 2 — Team A: CV = (5/50) × 100 = 10%. Team B: CV = (5/80) × 100 = 6.25%.
Step 3 — Lower CV means more consistent.
Answer: team B is more consistent. Key idea: CV compares spread relative to size — essential when the means differ.

Example 3 — Effect of scaling the data
Q: A data set has mean 20 and σ = 4. Each value is multiplied by 3, then 5 is added. Find the new mean and σ.
Step 1 — Multiplying by 3 scales both: mean → 60, σ → 12.
Step 2 — Adding 5 shifts the mean only: mean → 65.
Step 3 — Adding a constant leaves σ unchanged, so σ stays 12.
Answer: new mean 65, σ = 12. Key idea: spread is untouched by shifts but scales with multiplication.

Practice Statistics Quiz — 100% Free →

Frequently Asked Questions — Statistics

What are the key concepts in Statistics?
Mean, median, mode, standard deviation, and data interpretation
Is Statistics important for JEE?
Yes. Statistics is part of the Mathematics Class 11 NCERT syllabus and is directly tested in JEE examinations. StudyHub provides structured notes, diagrams, and practice questions covering all exam-level subtopics.
How can I practice Statistics questions on StudyHub?
Open StudyHub and select Mathematics → Statistics. Choose Easy, Medium, or Hard difficulty. Hard-tier questions are at JEE level with full step-by-step explanations.

References

  1. NCERT Class 11 Mathematics Textbook — Chapter: Statistics
  2. CBSE Curriculum — Mathematics (Class 11)
  3. NTA JEE Main Official Syllabus — subject-wise topic list